x^(2)-5x+1=0

Solve for x (where [*] denotes greatest integer function and {*} represent fractional part function) (i) [2x]=1 (ii) {x}^(2)+[x]=2 (iii) 6{x}^(2)-5{x}+1=0 (iv) 6{x}^(2)-5{x}-1=0

Determine whether the values given against each of the quadratic equations are the roots of the quadratic equation or not : x^(2)+4x-5=0,x=1,-1

The roots of 5x^(2) - x + 1 = 0 are

If domain of the function f(x)=sqrt(10x-x^(2)) is A then possible value(s) of x in A satisfying (6{x}^(2)-5{x}+1)=0 is/are (where {-} denotes fractional part function)

Verify whether the following functions can be regarded as the p.m.f for the given value of X : (1) P(X =x) ={:{(,(x^(2))/(5),x=0","1","2),(,0,"otherwise"):} (2) P(X = x) {{:(,(x-2)/(5),x=1","2","3","4),(,0,"otherwise"):}

Solve : x^4+4x^3+5x^2+4x+1=0

Solve the following equations : 2((x)/(x+1))^(2)-5((x)/(x+1))+2=0\ xne-1

Solve the following equations : 2((x)/(x+1))^(2)-5((x)/(x+1))+2=0\ xne-1