Volume of `2 M HCl` required to neutralise the solution containing `1"mole"` of `NH_(4)Cl` and `1 "mole"` of `NaOH` is:

The volume of 0.1 M HCl required in mL to neutralise 20 mL of a solution containing 0.106 g of Na_(2)CO_(3) is

Sulphuryl chloride SO_(2)Cl_(2) reacts with water to give a mixture of H_(2)SO_(4) and HCl . Moles of NaOH requried to neutralise the solution formed by adding 1 " mol of " SO_(2)Cl_(2) to excess water is are

Calculate the volume of 0.1 M NaOH solution required to neutralise the solution produced dissolving 1.1 g of P_(4)O_(6) in water.

The volume of 0.1 M H_2SO_4 required to neutralise 30 ml of 2.0 M NaOH is :

The volume of 0.1 M H_2SO_4 required to neutralise 50 ml of 0.2 M NaOH solution is

The ratio of pH of solution (1) containing 1 mole of CH_(3)COONa and 1 mole of HCl and solution (II) containing 1 mole of CH_(3)COONa and 1 mole of acetic acid in one litre is :

The ratio of pH of solution (1) containing 1 mole of CH_(3)COONa and 1 mole of HCl and solution (II) containing 1 mole of CH_(3)COONa and 1 mole of acetic acid in one litre is :