Tangent at `(-1,sqrt3)` on circle `x^2 + y^2 = 4`, becomes normal `(y != 0)` afterreflection from a line mirror `M_1`, such that angle between tangent and normalis `30^@`, then equation miror is -

Find the equations of the tangents and normal lines to the y = x^2 at (0, 0)

The angle between the tangents drawn from (0,0) to the circle x^(2)+y^(2)+4x-6y+4=0 is

The equation of a circle which has a tangent 3x+4y=6 and two normals given by (x-1)(y-2)=0 is

Show that the angle between the tangents drawn from (-1,3) to the circle x^(2)+y^(2)=5 is 90^(@) .

Show that the angle between the tangents drawn from (-1,3) to the circle x^(2)+y^(2)=5 is 90^(@) .

A circle is tangent to line 3x-4y+1=0 at (1,1) and is normal to line 2x+y-5=0 .then find the equation of circle

If theta is the angle between the tangents from (-1,0) to the circle x^(2)+y^(2)-5x+4y-2=0," then "theta=

From a point on the line 4x-3y=6 , tangents are drawn to the circle x^2 + y^2 -6x-4y+4=0 which make an angle of tan^(-1) (24/7) between them. Find the coordinates of all such points and the equation of tangents.

From a point on the line 4x-3y=6 , tangents are drawn to the circle x^2 + y^2 -6x-4y+4=0 which make an angle of tan^(-1) (24/7) between them. Find the coordinates of all such points and the equation of tangents.

Find the equations of the tangents and normal lines to the y = 2x^2 -3x - 1 at (1,-2)