A screw gauge gives the following reading when used to mesure the diametre of a wire.
Main scale reading : `0mm`
Circular scale reading : `52 divisions`
Given that `1mm` on main scale corresponds to `100` divisions of the circular scale. the diameter of wire from the above data is :

Explanation

Main scale reading `= 0mm`
Circular scale reading `= 52` divisions
Least count `= ("Value of 1 main scale division")/("Total divisions on circular scale") = (1)/(100) mm`
Diameter of wire `= M.S.R + (C.S.R xx L.C)`
`= 0 + 52 xx (1)/(100) mm = 0.52mm = 0.52cm`