The currect voltage relation of diode is given by `1=(e^(1000 V//T)-1) mA`, where the applied voltage V is in volt and the temperature T is in degree Kelvin. If a student makes an error measuring `+-0.01 V` while measuring the current of `5 mA` at `300 K`, what will be error in the value of current in mA?

Explanation

`I = (e^(1000V//T) - 1) mA`
`dV = +- 0.01V, T = 300K,I = 5mA`
`I + 1 = e^(1000V//T)`
`log(I + 1) = (1000V)/(T)`
`(dI)/(I + 1) = (1000)/(T) dV implies dI = 0.2mA`