The equilibrium constant for the reactions have been measured at 823 K.
`CoO(s) + H_(2)(g) hArr Co(s) + H_(2)O(g) , K = 67`
`CoO(s) + CO(g) hArr Co(s) + CO_(2) (g) , K = 490.`
From the data, calculate the equilibrium constant for the reaction.
`CO_(2)(g) +H_(2) (g) hArr CO(g) + H_(2)O (g)`

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

Equilibrium constant for the following reactions have been determined at 823K . CaO(s)+H_(2)(g)hArrCO(s)+H_(2)O(g) K_(1)=60 CaO(s)+CO(g)hArrCO(S)+CO_(2)(g) K_(2)=400 Using this information, calculate, equilibrium constant (at the same temperature) for :- CO_(2)(g)+H_(2)(g)hArrCO(s)+H_(2)O(g)K_(3)=? CO(g)+H_(2)O(g)hArrCO_(2)(g)+H_(2)(g)K_(4)=?

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

K_(p)//K_(c) for the reaction CO(g)+1/2 O_(2)(g) hArr CO_(2)(g) is

Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArr+CO(g)+H_(2)O(g)

Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArrCu(s)+CO_(2)(g)+H_(2)O(g)