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The final velocity fo a particles fallin...

The final velocity fo a particles falling freelly under graavity is given by `V^(2) - U^(2) = 2GX` WHERE `x` is the distance covered. IF `V = 18` kmph. `g = 1000 cm s^(-2), x = 120 cm` then `u = ...ms^(-1)`

A

`2.4`

B

`1.2`

C

`1`

D

`0.1`

Text Solution

Verified by Experts

The correct Answer is:
C
`v^(2) - u^(2) = 2gx` and change into `S.I`
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