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If the ratio of fundamental units in tow...

If the ratio of fundamental units in tow systems is `1:3`, then the ratio of momenta in the two system is

A

`1:3`

B

`1:9`

C

`1:27`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
A
`(M_(1))/(M_(2)) = (L_(1))/(L_(2)) = (T_(1))/(T_(2)) = (1)/(3), ((P_(1))/(P_(2))) = ((M_(1))/(M_(2))) = ((L_(1))/(L_(2))) = ((T_(1))/(T_(2)))^(-1)`
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