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In an experiment, the values of refracti...

In an experiment, the values of refractive indices of glass were found to be `1.54, 1.53, 1.44, 1.54, 1.56` and `1.45` in successive measurements (i) mean value of refreactive index of glass (ii) mean absolute error (iii) relative error and (iv) percentage error are respectively.

A

`1.51,0.04,0.03%, 3%`

B

`1.51,0.4,0.03%, 3%`

C

`15.1,0.04,0.03%, 3%`

D

`1.51,0.4,0.3%, 3%`

Text Solution

Verified by Experts

The correct Answer is:
A
`mu_("mean") = (sum mu)/(6), Delta u_("mean") = (sum(mu_("mean") - mu))/(6)`,
relative `%` error in `mu = (Delta mu_("mean"))/(mu_("mean")) xx 100`
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