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If the length of a simple pendulum is re...

If the length of a simple pendulum is recorded as `(90 +- 0.2)cm` and period as `(1.9 +- 0.02)s`, the percentage fo error in the measurement of acceleration due to gravity is

A

`4.2`

B

`2.1`

C

`1.5`

D

`2.8`

Text Solution

Verified by Experts

The correct Answer is:
B
`g = 4pi^(2) (l)/(T^(2)), (Delta g)/(g) xx 100 = (Delta l)/(l) xx 100 + (2Delta T)/(T) xx 100`
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