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In the relation P = (alpha)/(beta) e^(-a...

In the relation `P = (alpha)/(beta) e^(-alphaz//k theta),P` is preesure, `K` is Botzmann's constant, `Z` is distance and `theta` is temperature. The dimensional formula of `beta` wll be

A

`[M^(0) L^(2) T^(0)]`

B

`[M^(1) L^(2) T^(1)]`

C

`[ML^(2) T^(-1)]`

D

`[M^(0) L^(2) T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
A

`[(alpha z)/(k theta)] = 1`
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