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Measure of two quantities along with the...

Measure of two quantities along with the precision of respective measuring instrument is `A=2.5ms^(-1)+-0.5ms^(-1)`,B=0.10s+-0.01s`. The value of AB will be

A

`(0.25 +- 0.08)m`

B

`(0.25 +- 0.5)m`

C

`(0.25 +- 0.05)m`

D

`(0.25 +- 0.135)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`(Delta x)/(x) = (Delta A)/(A) + (Delta B)/(B)`
`= (0.5)/(2.5) + (0.1)/(0.10) = (0.5+0.025)/(0.25) = (0.075)/(0.25)`
`Delta x = 0.075 = 0.08m`, rounding off to two significant figures.
`AB = (0.25 +- 0.08)m`
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