Home
Class 11
PHYSICS
Young's modulus of steel is 1.9xx10^(11)...

Young's modulus of steel is `1.9xx10^(11) N//m^2` When expressed is CGS units of `dy"nes"// cm^2` it will be equal to `(1N = 10^5dy"ne", 1 m^2 = 10^4 cm^2)`

A

`1.9xx10^(10)`

B

`1.9xx10^(11)`

C

`1.9xx10^(12)`

D

`1.9xx10^(13)`

Text Solution

Verified by Experts

The correct Answer is:
C

Conversation of units
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise More than One Answer Questions|9 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise LEVEL-I (H.W)|39 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise LEVEL-III|21 Videos
  • TRANSMISSION OF HEAT

    NARAYNA|Exercise LEVEL-II(C.W)|27 Videos
  • VECTORS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

Young's modulu of steel is 1.9xx10^(11) N//m^2 When expressed is CGS units of dy"nes"// cm^2 it will be equal to (1N = 10^5dy"ne", 1 m^2 = 10^4 cm^2)

Young modulus of steel is 3 xx 10^(11) N//m^(2) . When expressed in C.G.S. unit of "Dyne"//cm^(2) it will be equal to

Young 's modulus of steel is 2.0 xx 10^(11)N m//(2) . Express it is "dyne"/cm^(2) .

Young's modulus of steel is 19xx10^(10) N//m^(2) Express it in "dyne"//cm^(2) . Here dyne is the CG unit of force.

Young's modulus of a metal is 21xx10^(10)N//m^(2) . Express it in "dyne/cm"^(2) .

The Young's modulus of steel is 1.9 xx 10^(11) Nm^(-2) . Calculate its value in dyne cm^(-2) .

Young's modulus of steel is 19xx10^10 N/m^2 . Expres it indyne/cm^2. Here dyne is the CGS unit of force.

If young's modulus of steel is 2xx10^(11)N//m^(2) , then the force required to increase the length of a wire of cross section 1 cm^(2) by 1% will be