Home
Class 11
PHYSICS
A student performs exeriment with simpl...

A student performs exeriment with simple pendulum and measures time for `10` vibrations. If the measures the time for `100` vibrations, the error in measurement of time period will be reduced by a factor of......

A

`10`

B

`90`

C

`100`

D

`1 overline(0)00`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to understand how the error in the measurement of the time period of a pendulum is affected by the number of vibrations measured. ### Step-by-Step Solution: 1. **Understanding the Concept**: The error in the measurement of time period (T) is inversely proportional to the square root of the number of vibrations (N) measured. This means that as the number of vibrations increases, the relative error decreases. 2. **Initial Measurements**: Let's denote: - \( N_1 = 10 \) (the number of vibrations in the first measurement) - \( T_1 \) = time measured for 10 vibrations - \( X \) = error in the measurement of time period when measuring 10 vibrations. 3. **Final Measurements**: Now, when the student measures the time for 100 vibrations: - \( N_2 = 100 \) (the number of vibrations in the second measurement) - \( T_2 \) = time measured for 100 vibrations - \( X' \) = error in the measurement of time period when measuring 100 vibrations. 4. **Error Relationship**: The relationship between the errors can be expressed as: \[ \frac{X'}{X} = \frac{N_1}{N_2} \] This indicates that the error in the second case (when measuring 100 vibrations) is reduced compared to the first case (when measuring 10 vibrations). 5. **Substituting Values**: Substitute the values of \( N_1 \) and \( N_2 \): \[ \frac{X'}{X} = \frac{10}{100} = \frac{1}{10} \] 6. **Calculating the Factor of Reduction**: From the equation above, we can express \( X' \) as: \[ X' = X \cdot \frac{1}{10} \] This shows that the error \( X' \) in the measurement of time period when measuring 100 vibrations is \( \frac{1}{10} \) of the original error \( X \). 7. **Conclusion**: Therefore, the error in measurement of the time period will be reduced by a factor of 10. ### Final Answer: The error in measurement of the time period will be reduced by a factor of **10**. ---

To solve the problem, we need to understand how the error in the measurement of the time period of a pendulum is affected by the number of vibrations measured. ### Step-by-Step Solution: 1. **Understanding the Concept**: The error in the measurement of time period (T) is inversely proportional to the square root of the number of vibrations (N) measured. This means that as the number of vibrations increases, the relative error decreases. 2. **Initial Measurements**: ...
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise LEVEL-II (H.W)|20 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise ILLUSTRATION|49 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise More than One Answer Questions|9 Videos
  • TRANSMISSION OF HEAT

    NARAYNA|Exercise LEVEL-II(C.W)|27 Videos
  • VECTORS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

We can use a simple pendulum to measure the time.

Time period of simple pendulum increase with

If Y=a times b, the maximum percentage error in the measurement of Y will be

The time taken to perform 30 vibrations is 30 times the time taken for a single vibration.

Define the term time period of vibration.

NARAYNA-UNITS AND MEASUREMENTS-LEVEL-I (H.W)
  1. If the length and beradth of a plate are (5.0 +- 0.2)cm and (4.0 +- ...

    Text Solution

    |

  2. If the length of a cylinder is measured to be 8.28cm with an error of ...

    Text Solution

    |

  3. A student performs exeriment with simple pendulum and measures time f...

    Text Solution

    |

  4. If L(1) = (3.03 +- 0.02)m and L(2) = (2.01 +- 0.02)m then L(1) + 2L(2)...

    Text Solution

    |

  5. A body travels uniformly a distance of ( 13.8 +- 0.2) m in a time (4.0...

    Text Solution

    |

  6. The pressure on a square plate is mesaurement by measuring the force...

    Text Solution

    |

  7. 2.34 is obtained by rounding off the number

    Text Solution

    |

  8. The number of singnificant figures in 0.0006032 is

    Text Solution

    |

  9. The radius of disc is 1.2cm its area according to idea of significant ...

    Text Solution

    |

  10. When Energy is expressed in erg the no of significant figure is four. ...

    Text Solution

    |

  11. sqrt(58.97) is

    Text Solution

    |

  12. A stick has a length of 12.132cm and an other stick has a length of 12...

    Text Solution

    |

  13. The respective number of signficant figures for the numbers 23.023, 0...

    Text Solution

    |

  14. The number of significiant figures in 5.69 xx 10^(15) kg is

    Text Solution

    |

  15. The value of 124.2 + 52.487 with due regard to significant places is....

    Text Solution

    |

  16. The value fo (9.270)/(41) with due regard to significant figures is.....

    Text Solution

    |

  17. When 57.986 is rounded off to 4 significant figures, then it becomes....

    Text Solution

    |

  18. If 'L' is length of sample pendulum and 'g' is acceleration due to gra...

    Text Solution

    |

  19. The demensional formula for the product of two physical quantites P an...

    Text Solution

    |

  20. The fundamental physical quantites that have same dimesions in the di...

    Text Solution

    |