A carrier wave of `1000W` is subjected to `100%` modulation. Calculate (`i`) Power of modulated wave, (`ii`) power is `USB`, (`iii`) power is `LSB`

Explanation

(`i`) Total pressure of modulated wave
`P_(T)=P_(C)(1+(m^(2))/(2))`, `=1000(1+(1^(2))/(2))=1500watt`
(`ii`) Power in `USB=(1)/(2)P_(SB)`
Where power carried by side bands is given by amplitude modulation and detection
`P_(SB)=P_(C)((m^(2))/(2))`, `=1000((1^(2))/(2))=500watt`
`P_(USB)=(1)/(2)P_(SB)=(1)/(2)xx500=250watt`
(`iii`) Since power in `LSB=` Power in `USB`
`P_(LSB)=P_(USB)=250watt`