An amplitude modulated wave is modulated to `50%`. What is the saving in power if carrier as well as one of the side band are suppressed?

Explanation

as total power `P_(t)=P_(c)+P_(SB)`
Here `P_(c)=(A^(2))/(2R)`
and `P_(SB)=P_(LSB)+P_(USB)` as `P_(LSB)=P_(USB)=(mu^(2)A_(c)^(2))/(8R)`
`P_(SB)=(mu^(2)A_(c)^(2))/(4R)`
`%` Saving `=(P_(c)+P_(LSB))/(P_(t))xx100`
`=((A^(2))/(2R)+(mu^(2)A_(c)^(2))/(8R))/((A_(c)^(2))/(2R)+(mu^(2)A_(c)^(2))/(4R))xx100=((1)/(2)+(mu^(2))/(8))/((1)/(2)+(mu^(2))/(4))xx100`
Given `mu=(50)/(100)=(1)/(2)`
Substituting , we get `%` saving `=94.4%`