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The maximum distance between the transmi...

The maximum distance between the transmitting and receving TV towers is `72 km`. If the ratio of the heights of the TV transmitting tower to receiving tower is `16 : 25`, the heights of the transmitting and receiving tower are

A

`51.2m`, `80m`

B

`40 m` , `80 m`

C

`80 m`, `125 m`

D

`25 m` , `75 m`

Text Solution

Verified by Experts

The correct Answer is:
C
`(h_(t))/(h_(r))=(16)/(25)`, `d=sqrt(2Rh_(t))+sqrt(2Rh_(r))`
`72xx10^(3)=sqrt(2R(16)/(25)h_(r))+sqrt(2Rh_(r))`
`impliesh_(r)=125m` & `h_(t)=80m`
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Knowledge Check

  • The maximum distance between the transmitting and receving TV towers is 64 km . If the ratio of the heights of the TV transmitting tower to receiving tower is 4 : 9 , the heights of the transmitting and receiving tower are

    A
    `51.2 m`, `80m`
    B
    `1280m`, `2880m`
    C
    `80m`, `125m`
    D
    `25m`, `75m`

  • If the TV telecast is to cover a radius of 120 km ( Given , the radius of the earth = 6400 km ), the height of the transmitting antenna is

    A
    1280 m
    B
    1125 m
    C
    1560 m
    D
    79 m

  • The maximum distance upto which TV transmission from a TV tower of height h can be received is proportional to

    A
    `h^(1//2)`
    B
    `h`
    C
    `h`
    D
    `h^(2)`

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