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An AM wave is given by V=1500[1+0.5sin...

An `AM` wave is given by
`V=1500[1+0.5sin12560t]sin(5.26xx10^(5)t)`.
The modulating frequency is

A

`2.0 kHz`

B

`1.0 kHz`

C

`12.5 kHz`

D

`50 kHz`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(m)(t)=A_(c)(1+musin omega_(m)t)sin omega_(c)t`
`f_(m)=(omega_(m))/(2pi)=(12560)/(2pi)=2khz`
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