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A given AM transmitter develops an unmod...

A given `AM` transmitter develops an unmodulated power out put of `1 KW` across `50 Omega` resistance. When a message signal of amplitude `5 V` is applied on it then the side bands carry `40%` of power of carrier. Amplitude of the carrier signal used is

A

`505.952 V`

B

`126.488`

C

`252.976`

D

`316.22`

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(c)=(A_(C)^(2))/(2R)=1kWimplies(A_(c)^(2))/(2xx50)=10^(3)`
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