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An audio signal 5sin2pi(1600t) amplitude...

An audio signal `5sin2pi(1600t)` amplitude modulates `20sin2pi(10^(5)t)`. The two side band frequencies are

A

`98.4 kHz`, `101.6 kHz`

B

`92.5 kHz`, `105.5 kHz`

C

`32.1 kHz`, `31.59 kHz`

D

`96 kHz`, `106 kHz`

Text Solution

Verified by Experts

The correct Answer is:
A
`LSB=f_(c)-f_(m)=10^(5)-1600=98.4KHz`
`USB=f_(c)+f_(m)=10^(5)+1600=101.6KHz`
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