If `f:{1,2,3,4} ->{1,2,3,4}`, y = f(x) be a function such that `|f(alpha) - alpha| <1` for `alpha in {1,2,3,4}` then total number of functions are

If f:{1,2,3,4}rarr{1,2,3,4},y=f(x) be a function such that |f(alpha)-alpha|<1 for alpha in{1,2,3,4} then total number of functions are

If f(x) = x^2 - 3x + 1 and f (2 alpha) = 2 x f(alpha) =

If A={1,2,3,4} and f : A->A, then total number of invertible functions,'f',such that f(2)!=2 , f(4)!=4 , f(1)=1 is equal to:

If A={1,2,3,4} and f : A->A, then total number of invertible functions,'f',such that f(2)!=2,f(4)!=4,f(1)=1 is equal to:

Let f(x)=cot^(-1)(x^2+4x+alpha^2-3alpha) be a function defined on R->(0,pi/2] , is an onto function then (a) alpha in [-1,4] (b) alpha in {-1,4} (c) f(x) is one-one (d) f(x) is many-one

Let f : R rarr R be a differentiable function satisfying f(x) = f(y) f(x - y), AA x, y in R and f'(0) = int_(0)^(4) {2x}dx , where {.} denotes the fractional part function and f'(-3) - alpha e^(beta) . Then, |alpha + beta| is equal to.......

Let f(x)a n dg(x) be two continuous functions defined from RvecR , such that f(x_1) > f(x_2) and g(x_1) x_2 dot Then what is the solution set of f(g(alpha^2-2alpha) > f(g(3alpha-4))

Let f(x)a n dg(x) be two continuous functions defined from RvecR , such that f(x_1) > f(x_2) and g(x_1) x_2 dot Then what is the solution set of f(g(alpha^2-2alpha) > f(g(3alpha-4))

Let f(x)a n dg(x) be two continuous functions defined from RvecR , such that f(x_1) > f(x_2) and g(x_1) x_2 dot Then what is the solution set of f(g(alpha^2-2alpha) > f(g(3alpha-4))

Let f(x) :R->R,f(x)={(2x+alpha^2,xge2),((alpha x)/2+10,x lt 2)) If f(x) is onto function then alpha belongs to (A) [1,4] (B) [-2,3] (C) [0,3] (D) [2,5]