" 11."16x-(10)/(x)=27quad " [CBSE "2014]" y "sqrt(3)x^(2)

If sqrt(3x^(2)-12x + 19) + sqrt(3x^(2)-12x-11)= 16 then find sqrt(3x^(2)-12x + 19) - sqrt(3x^(2) -12x-11) = ?

The derivative of y=sin^(-1)((3x+sqrt(16-16x^(2)))/(5)) with respect to x at x=(sqrt(3))/(2) , is

(3)/(2)x^(2)+16x+10

Suppose that, log_(10) (x-2) + log_(10) y=0 and sqrt(x)+sqrt(y-2)=sqrt(x+y) . Then the value of (x + y) , is

Suppose that, log_(10) (x-2) + log_(10) y=0 and sqrt(x)+sqrt(y-2)=sqrt(x+y) . Then the value of (x + y) , is

Solve by factorization: 16x-(10)/(x)=27

int(3x^2)/sqrt(9-16x^6)dx

Subtract 11x^(3) -7x^(2) + 10x from 16x^(3) + 4x^(2) -11x