Read the screw gauge shown below in the figure.
Given that circular scale has ` 100` divisions and in one complete rotation the screw advances by `1 mm`.
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Find the thickness of the wire The main scale division is of 1mm In a complete rotation the screw advances by 1mm and the circular scale has 100 devisions

Read the screwgaug shown bellow Main scale has (1)/(2)mm marks In complete rotation the screw advances by (1)/(2)mm Circular scale has 50 division .

In a screw gauge, the main scale has divisions in millimetre and circular scale has 50 divisions. The least count of screw gauge is

Two measure diameter of a wire a screw-gauge is used The main scale division is of 1mm In a complete rotation the screw advances by 1mm and the circular scale has 100 divisions The reading of screw-gauge is as shown in If there is no error is no error in mass measurement but error in length measurement is 1% then find max Possible error in density if diameter is 3.07 mm.

The given diagram represents a screw gauge. The circular scale is divided into 50 divisions and the linear scale is divided into millimeters. If the screw advances by 1 mm when the circular scale makes 2 complete revolutions, find the least count of the instrument and the reading of the instrument in the figure. .

The given diagram represents a screw gauge. The circular scale is divided into 50 divisions and the linear scale is divided into millimeters. If the screw advances by 1 mm when the circular scale makes 2 complete revolutions, find the least count of the instrument and the reading of the instrument in the figure. .