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" i) "(11)/(4-sqrt(5))...

" i) "(11)/(4-sqrt(5))

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the value of |((3-i sqrt(2))^(2))/(1+i2)| is equal to (i) (11)/(sqrt(5)) (ii) (18)/(sqrt(7)) (iii) (5)/(sqrt(11)) (iv) (13)/(sqrt(3))

If x=(11)/(4-sqrt(5)), find the value of x^(2)-8x+11

Simplify : (sqrt(5)+sqrt(2))^(2) (ii) (sqrt(11)-sqrt(5))^(2)

Simplify : (i) (sqrt(5)+sqrt(2))^2 (ii) (sqrt(11)-sqrt(5))^2

Simplify : (i) (sqrt(5)+sqrt(2))^2 (ii) (sqrt(11)-sqrt(5))^2

Find the values of a and b in each of the following : (a)(5+2sqrt3)/(7+4sqrt(3))=a-6sqrt(3)" "(b)(3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-(19)/(11) (c )(sqrt(2)+sqrt(3))/(3sqrt2-2sqrt(3))=2-bsqrt(6)" "(d)(7+sqrt(5))/(7-sqrt(5))-(7-sqrt(5))/(7+sqrt(5))=a+(7)/(11)sqrt(5b)

Find the values of a and b in each of the following : (a)(5+2sqrt3)/(7+4sqrt(3))=a-6sqrt(3)" "(b)(3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-(19)/(11) (c )(sqrt(2)+sqrt(3))/(3sqrt2-2sqrt(3))=2-bsqrt(6)" "(d)(7+sqrt(5))/(7-sqrt(5))-(7-sqrt(5))/(7+sqrt(5))=a+(7)/(11)sqrt(5b)

Rationalise the denominator of (11)/(5+sqrt(3))

Rationalise the denominator of (11)/(5+sqrt(3))

ln Delta ABC , tan A=3 , tan B=(2)/(3) c=sqrt(10) then circum radius of Delta is (1) 11sqrt((13)/(10)) (2) (10sqrt(13))/(11) (3) (sqrt(130))/(11) (4) (5sqrt(13))/(11)