lambda'*42*x^(2)+5x-(a^(2)+a-6)=0

the values of lambda for which (lambda^(2)-3 lambda+2)x^(2)+(lambda^(2)-5 lambda+6)+lambda^(2)-4=0 is identity in x is

The equation lambda^(2)x^(2)+(lambda^(2)-5 lambda+4)xy+(3lambda-2)y^(2)-8x+12y-4=0 will represent a circle, if lambda=

The equation lambda^(2)x^(2)+(lambda^(2)-5 lambda+4)xy+(3lambda-2)y^(2)-8x+12y-4=0 will represent a circle, if lambda=

If the equation (lambda^(2)-5 lambda+6)x^(2)+(lambda^(2)-3 lambda+2)x+(lambda^(2)-4)=0 is satisfied by more then two values of x then lambda=

If the equation lambda x^(2)-5 x y+6 y^(2)+x-3 y=0 represents a pair of lines, then their point of intersection is

The value of lambda for which the equation lambda^2 - 4lambda + 3+ (lambda^2 + lambda -2)x + 6x^2 - 5x^3 =0 will have two roots equal to zero is

If 2x^(2)+lambda xy^(+)2y^(2)+(lambda-4)x+6y-5=0 is the equation of a circle,then its radius is :