[113sec alpha-5tan alpha=k" and "6sec alpha+k tan alpha=5" then "k^(2)=,],[1120,225]

If 3 sec alpha- 5 tan alpha= k and 6 sec alpha+k tan alpha=5 then k^(2)=

If 3sec alpha-5tan alpha=k and 6sec alpha+k tan alpha=5 then k^(2)=(i)20(ii)25 (iii) 34 (iv) 37

If a sec alpha+ b tan alpha= 1 and a^(2) sec^(2) alpha-b^(2) tan^(2) alpha=5 then 4a^(2)-9b^(2)=

(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alpha)/(tan2 alpha)

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha - d tan alpha=c , then eliminate alpha from above equations.

If : a * sec alpha+b * tan alpha=m and : atan alpha+b * sec alpha=n, then : a^(2)-b^(2) =

" If "alpha=(2 pi)/(7)" ,and "tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha=K" .Then "3k^(2)+4k+5=" ."

(1)/(sec alpha - tan alpha ) - (1)/( cos alpha)=