" If "a+b=1," then "sum(r=0)^(n)C(n,r)a^...

" If "a+b=1," then "sum_(r=0)^(n)C(n,r)a^(r)b^(n-r)" is equal to "

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If a+b=1, then sum_(n=0)^(n)C(n,r)a^(r)b^(n-r) is equal to '

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