" Solve; "x log x(dy)/(dx)+y=2log x

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Solve x log x(dy)/(dx) + y = 0

The solution of x log x (dy)/(dx) + y = 2 log x is

(x log x ) (dy)/(dx) + y = 2 log x

solve (dy)/(dx)=log x

Solve : x log x dy/dx+y=2/x log x .

Solve (x log x ) ( dy)/(dx) + y = (2)/(x) log x .

Solve the following differential equations x log x (dy)/(dx) + y = 2/x log x