((1+2)^(2))/(3-i)

The conjugate of ((1+2i)^(2))/(3-i) is

The conjugate of ((1+2i)^(2))/(3-i) is

Express the following complex numbers in the standard form a+ib:((2+1)^(3))/(2+3i)

(1+2i+3i^(2))/(1-2i+3i^(2)) equals i b.-i c.-1 d.4

The sum of the first 20 terms of the series (1)/(i)+(2)/(i^(2))+(3)/(i^(3))+.... is :

abs(1/((3 +i)^2)-1/((3-i)^2)) =

Convert ((1)/(2)+2i)^(3) in the form of a+ib .

Convert ((1)/(2)+2i)^(3) in the form of a+ib .

If z=(-2(1+2i))/(3+i) where i=sqrt(-1) then argument theta(-pilt thetalepi) of z is

Convert each of the following in the form of (a + i b) : (i) 3(1+i)-2(2+3i) (ii) (1)/(4-5i) (iii) (1-2i)^(-2) (iv) (2-3i)/(3+5i) (v) [(1)/(1-2i)+(3)/(1+i)][(3+4i)/(2-4i)]