Tangents are drawn from the origin to curve `y=sinxdot` Prove that points of contact lie on `y^2=(x^2)/(1+x^2)`

Tangents are drawn from the origin to curve y=sin x. Prove that points of contact lie on y^(2)=(x^(2))/(1+x^(2))

Tangents are drawn from the origin to the curve y=cos X. Their points of contact lie on

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

3.(1) x + y = 0(2) x - y = 0If tangents are drawn from the origin to the curve y = sin x, then their points of contact lie on the curve(3) x2 - y2 = x2y2 (4) x2 + y2 = x2y2(2) x + y = xy(1) X- y = xy

Tangents are drawn from origin to the curve y=sin+cos x Then their points of contact lie on the curve

Tangents are drawn to the curve y=sin x from the origin.Then the point of contact lies on the curve (1)/(y^(2))-(1)/(x^(2))=lambda. The value of lambda is equal to

If tangents are drawn from origin to the circle x^(2)+y^(2)-2x-4y+4=0, then