The upper part of a tree broken over by the wind makes an angle of `30^@` with the ground and the distance from the root to the point where the top of the tree touches the ground is 15 m. Using sine rule, find the height of the tree.

The upper part of a tree broken over by the wind makes an angle of 30^0 with the ground and the distance from the root to the point where the top of the tree touches the ground is 15m. Using sine rule, fine the height of the tree.

The upper part of a tree broken over by the wind makes an angle of 30^(@) with the ground and the distance from the root to the point where the top of the tree toches the goint is 15m. Using sine rule,fine the height of the tree.

The upper part of a tree broken over by the wind makes an angle of 30^(@) with the ground and the distance from the root to the point where the top of the tree touches the ground is 10 m. The height of the tree is:

The upper part of a tree, broken over by the wind. makes an angle of 45^(@) with the ground , and the distance from the root to the point where the top of the tree touches the ground. is 1.5 m. What was the height of the tree before it was broken ?

The upper part of a tree broken over by the wind makes an angle of 60^(@) with the ground and the horizontal distance from the foot of the tree to the point where the top of the tree meets the ground is 10 metres. Find the height of the tree before broken.

The upper part of a tree broken over by the wind makes an angle of 60^(@) with the ground and the horizontal distance from the foot of the tree to the point where the top of the tree meets the ground is 10 metres. Find the height of the tree before broken.

The upper part of a tree is broken by wind and makes an angle of 30^(@) with the ground and at a distance of 21m from the foot of the tree. Find the total height of the tree.