The intensity of X-rays decreases exponentially according to the law `I=I_(0)e^(-mux)` , where `I^(0)` is the initial intensity of X-rays and I is the intensity after it penetrates a distance x through lead. If `mu` be the absorption coefficient, then find the dimensional formula for `mu` .

The intensity of a light pulse travelling along a communication channel decreases exponentially with distance x according to the relation I=I_0 e^(-alpha x) , where I_0 is the intensity at x = 0 and alpha is the attenuation constant. What is the distance travelled by the wave, when the intensity reduces by 75% of its initial intensity?

The intensity of an X-ray beam reduces to 36.8% of its initial intensity after traversing a gold film of thickness 5xx10^(-3)m . Its absorption coefficient is

The intensity of light pulse travelling in an optical fiber decreases according to the relation I=I_(0)e^(-alpha x) . The intensity of light is reduced to 20% of its initial value after a distance x equal to

The intensity of a light pulse travelling along a communication channel decreases exponetially with distance x according to the relation I=I_(0)e^(-ax) where I_(0) is the intensity at x=0 and alpha is the attenuation constant. The percentage decrease in intensity after a distance of (("In"4)/(alpha)) is

The intensity of a light pulse travelling along an optical fibre decreases exponentially with distance according to the relation l = i_(0) e^(-0.0693x) where x is in km and l_(0) is intensity of incident pulse. The intensity of pulse reduces to (1)/(4) after travelling a distance