In a circle with center O and radius 5 cm AB is a chord of length `5sqrt(3)` cm. FInd the area of `triangleAOB`

Explanation

Here, we are given,

`AB = 5sqrt3cm, OA = 5cm`

Let `OX` is the perpendicular to `AB`.

then, `AX = XB = (5sqrt3)/2cm`

So, in right angle triangle `OAX`,

`OA^2=OX^2 +AX^2`

`=>5^2 = OX^2+((5sqrt3)/2)^2`

`=>25 = OX^2+75/4`

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