If the kinetic energy of a particle is doubled, De-Broglie wavelength becomes :

If the kinetic energy of a moving particle is E , then the de-Broglie wavelength is

If the kinetic energy of a moving particle is E , then the de-Broglie wavelength is

If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factor

If the kinetic energy of a free electron doubles , its de - Broglie wavelength changes by the factor

Calculate the kinetic energy of an alpha -particle which has a de broglie wavelength 8 pm.

The de Broglie wavelength and kinetic energy of a particle is 2000 Å and 1 eV respectively. If its kinetic energy becomes 1 MeV, then its de Broglie wavelength becomes

If the momentum of a particle is doubled, then its de-Broglie wavelength will

Kinetic energy of the particle is E and it's De-Broglie wavelength is lambda . On increasing it's KE by delta E , it's new De-Broglie wavelength becomes lambda/2 . Then delta E is