A weight of 100N is suspended by two wires made by steel and copper as shown in figure length of steel wire is 1m and copper wire is `sqrt(3)m`. Find ratio of change in length of copper wire `(Deltal_(c))` to change in length of steel wire `(Deltal_(s))`. given Young's modulus `Y_("Steel") =2xx10^(11) N//m^(2),Y_("Copper")=1xx10^(11) N//m^(2)`

Two wires, one made of capper and other of steel are joined end to end. (as show in figure). The area of cross-section of copper wire is twice that of steel wire, They ae placed under compressive force of magnitude F. Find the ratio of their lenghts such that change in lenght of both wire are same (Y_(S)= 2 xx 10 ^(11) N//m^(2) and Y_(C) = 1.1 xx 10 ^(11) N//m^(2))

A block of weight 100 N is suspended by copper and steel wires of same cross sectional area 0.5 cm^(2) and, length sqrt(3) m and 1m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30^(@) and 60^(@) , respectively. If elongation in copper wire is (Delta l_(C)) and elongation in steel wire is (Delta l_(s)) , then the ratio (Delta l_(C))/(Delta l_(s)) is - [Young's modulus for copper and steel are 1 xx 10^(11) N//m^(2) and 2 xx 10^(11) N//m^(2) , respectively]

A block of weight 100 N is suspended by copper and steel wires of same cross sectional area 0.5 cm^(2) and, length sqrt(3) m and 1m, respectively. Their other ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30^(@) and 60^(@) , respectively. If elongation in copper wire is (Delta l_(C)) and elongation in steel wire is (Delta l_(s)) , then the ratio (Delta l_(C))/(Delta l_(s)) is - [Young's modulus for copper and steel are 1 xx 10^(11) N//m^(2) and 2 xx 10^(11) N//m^(2) , respectively]

Two exactly similar wire of steel and copper are stretched by equal force. If the difference in their elongations is 0.5 cm, the elongation (l) of each wire is Y_(s)("steel") =2.0xx10^(11) N//m^(2) Y_(c)("copper")=1.2xx10^(11)N//m^(2)

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

What is the work done per unit volume when a steel wire is stretched by 0.2% of its original length ? (Young's modulus of steel is 2xx10^(11)N//m^(2) )

Two exactly similar wires of steel and copper are stretched by equal force. If the total elongation is 2 cm, then how much is the elongation in steel and copper wire respectively? Given, Y_("steel")=20xx10^(11)"dyne/cm"^(2),Y_("copper")=12xx10^(11)"Dyne/cm"^(2)

Two exactly similar wires of steel and copper are stretched by equal force. If the total elongation is 2 cm, then how much is the elongation in steel and copper wire respectively? Given, Y_("steel")=20xx10^(11)"dyne/cm"^(2),Y_("copper")=12xx10^(11)"Dyne/cm"^(2)

Two wires one of copper and other of steel having same cross-sectionl area end to end and strecteched by a load M. Ifcopper wire Is stretched by 1 mm, the total extnsion of the combined wire is (Givwen, Young's are Y_("copper")= 1 xx 10^(11) N//m^(2), and Y_("steel") = 2 xx 10^(11) N//m^(2))