Solve the equations.`2tan^(-1)(cosx)=tan^(-1)(2cose c x)`

Explanation

To solve the equation \( 2\tan^{-1}(\cos x) = \tan^{-1}(2\cos x) \), we can follow these steps:

### Step 1: Use the Double Angle Formula for Inverse Tangent
We know that:
\[ \tan^{-1}(a) + \tan^{-1}(b) = \tan^{-1}\left(\frac{a + b}{1 - ab}\right) \]
If we let \( a = \cos x \) and \( b = \cos x \), then:
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