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(cos theta)/(sec Q-tan Q)=1+sin theta...

(cos theta)/(sec Q-tan Q)=1+sin theta

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Prove that (cos theta)/(1+sin theta)=(1-sin theta)/(cos theta)=sec theta-tan theta

Prove: (cos theta)/(1+sin theta) = sec theta - tan theta

(cos theta)/(sec theta-tan theta)=1+sin theta

Show that (tan theta+sec theta -1)/(tan theta - sec theta +1)=(1 + sin theta)/(cos theta)

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

Prove that (tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)