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The equation of two light waves are y(1)...

The equation of two light waves are `y_(1)=6cosomegat,y_(2)=8cos (omegat+phi)`.The ratio of maximum to minimum intensities produced by the supersposition of these waves will be-

A

`49:1`

B

`1:49`

C

`1:7`

D

`7:1`

Text Solution

AI Generated Solution

To find the ratio of maximum to minimum intensities produced by the superposition of the two light waves given by the equations \( y_1 = 6 \cos(\omega t) \) and \( y_2 = 8 \cos(\omega t + \phi) \), we can follow these steps: ### Step 1: Identify the Amplitudes From the given equations, we can identify the amplitudes of the two waves: - Amplitude of \( y_1 \) (denoted as \( A_1 \)) = 6 - Amplitude of \( y_2 \) (denoted as \( A_2 \)) = 8 ### Step 2: Calculate Maximum Amplitude ...
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