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A young's experiment ,the separation bet...

A young's experiment ,the separation between the slits is `0.10mm`.the wavelength of light is used is `600nm`and the interfernce pattern is observed on screen`1.0m`away,Find the separation between the successive bright firgness.

A

`6.6mm`

B

`6.0mn`

C

`6m`

D

`6cm`

Text Solution

Verified by Experts

The sparation between the successive bright fringes is -
`beta=(Dlambda)/(d)=(1xx600xx10^(-9))/(1xx10^(-3))`
`beta=6.0mm`
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