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When wave of wavelength 0.2cmis made inc...

When wave of wavelength `0.2cm`is made incident normally ona slit of width `0.004m`then the semui-angular width of central maximum of diffraction patten will be-

A

`60^(@)`

B

`30^(@)`

C

`90^(@)`

D

`0^(@)`

Text Solution

Verified by Experts

The correct Answer is:
2
`theta=sin^(-1)((lambda)/(a))`….(1)
According to the question
` lambda=2xx10^(-3)m`
`a=4xx10^(-3)m…..(2)`
From equation (1) and(2)
`theta=sin^(-1)""(1)/(2) rArr theta=30^(@)`
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