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Light of wavelength 6328Å is incident no...

Light of wavelength `6328Å` is incident normally on slit having a width of `0.2mm`The width of the central maximum measured form minimum to minimum of diffraction pattens on a screen `9.0meter`away will be about-

A

`0.36^(@)`

B

`0.18^(@)`

C

`0.72^(@)`

D

`0.09^(@)`

Text Solution

Verified by Experts

The correct Answer is:
1
Silit width =`a=0.2mm,beta=(2lambdaD)/(a)`
Angular width `W_(theta)=(beta)/(D)=(2lambda)/(a) rArr theta =(2xx6328)/(0.2)=0.36^(@)`
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