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Light of wavelength 520nm passing throug...

Light of wavelength `520nm` passing through a double slit,produced interference pattern of relative intensity versus deflection angle `theta` as shown in the figure.find the separation of between the slits.

Text Solution

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The correct Answer is:
`1.99xx10^(-2)mm`

Angular width of frings `theta=(lambda)/(d)…(1)`
given that `theta=1.5^(@) rArr theta=(3^(@))/(2)`
from (1)&(2) `(lambda)/(d)=(3)/(2)xx(pi)/(180) ….(2)`
`d=(120lambda)/(pi) rArr d=(120xx520xx10^(-9))/(3.14)`
`d=1.98xx10^(-5)m rArr d=1.98xx10^(-2)mm`
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