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Two beam of light having intensities I a...

Two beam of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between resultant intensities at A and B is : `(2001 , 2M)`

A

`2I`

B

`4I`

C

`5I`

D

`7I`

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(R)=I_(1)+I_(2)+2sqrt(I_(1)I_(2))cosphi,`
`I_(R_(1))=I_(1)+I_(2)+2sqrt(I_(1)I_(2)) cos pi//2 implies I_(R_(1))=I_(1)+I_(2)`
`I_(R_(2))=I_(1)+I_(2)+2sqrt(I_(1)I_(2)) cos pi rArr I_(R_(2))=I_(1)+I_(2)+2sqrt(I_(1)I_(2))`
`I_(R_(1))-I_(R_(2))=2sqrt(I_(1)I_(2)) rArr I_(R_(1))-I_(R_(2))=2sqrt(I.4I)`
`I_(R_(1))-I_(R_(2))=4I`
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