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Light of wavelength lambda in air enters...

Light of wavelength `lambda` in air enters a medium of refractive index `mu`. Two points in this medium, lying along the path of this light, are at a distance of x apartThe phase difference between these point is

A

`(2pimux)/(lambda)`

B

`(2pix)/(mu lambda)`

C

`(2pi(mu-1)x)/(lambda)`

D

`(2pix)/((mu-1)lambda)`

Text Solution

Verified by Experts

The correct Answer is:
A

Optical path diff.=`mux`
`(phi)/(2pi)=(mux)/(lambda)`
`phi=(2pimux)/(lambda)`
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