" " If "x=sin theta,y=sin^(3)theta" then "(d^(2)y)/(dx^(2))" at "theta=(pi)/(2)" is "

If x=sintheta,y=sin^(3)theta then (d^(2)y)/(dx^(2)) at theta=(pi)/(2) is . . .

If x=acos^3theta,y=a sin^3theta then find (d^2y)/(dx^(2))

If x=acos^3theta,y=a sin^3theta then find (d^2y)/(dx^(2))

If x=a cos theta,y=b sin theta, then (d^(2)y)/(dx^(2)) when theta=(pi)/(4) is given by

If x=2 cos theta-cos 2 theta and y=2 sin theta-sin 2 theta , then the value of (d^(2)y)/(dx^(2)) at theta=(pi)/(2) is -

If x =a cos ^(3) theta, y= a sin ^(3) theta then (d^(2) y)/( dx ^(2)) at theta = pi //4 is

If x =a ( theta + sin theta), y =a (1 - cos thea) then (d ^(2) y)/(dx ^(2)) at theta = (pi)/(4) is

If x = a(1+ cos theta), y = a (theta + sin theta) , then (d^(2)y)/(d x^(2)) at theta = (pi)/(2) is

If x =theta -sin theta ,y=1-cos theta,then (d^(2)y)/(dx^(2))=