[" 5."7(y+3)-2(x+2)=14],[4(y-2)+3(x-3)=2]

Solve the following system of equations: 7(y+3)-2(x+2)=14,quad 4(y-2)+3(x-3)=2

Solve the following system of equations: 7(y+3)-2(x+2)=14 ,\ \ \ \ \ 4(y-2)+3(x-3)=2

Find the following products: (x+2)(x+3) (ii) (x+7)(x-2)y-4)(y-3)( iv )(y-7)(y+3)(2x-3)(2x+5)( vi )(3x+4)(3x-5)

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

{:(3x + 2y = 4),(2x - 3y = 7):}

{:(3x + 2y = 4),(2x - 3y = 7):}

3x+2y=14; x+4y=7

Identify the type of conic section for each of the equations 1. 2x^(2) -y^(2) = 7 2. 3x^(2) +3 y^(2) -4x + 3y + 10 =0 3. 3x^(2) + 2y^(2) = 14 4. x^(2) + y^(2) + x-y=0 5. 11x^(2) -25y^(2) -44x + 50y - 256 =0 6. y^(2) + 4x + 3y + 4=0

Find the following products: (i) (x+2)(x+3) (ii) (x+7)(x-2) (iii) y-4)(y-3) (iv) (y-7)(y+3) (vi) (2x-3)(2x+5) (vii) (3x+4)(3x-5)