[" (1) "A=[[0],[-tan alpha],[2]]-tan alpha/2],[" Ance "(J+A)=(I-A)[[cos alpha],[sin alpha]]]

If A=,[[0,-tan((alpha)/(2))]tan((alpha)/(2)),0]], then I+A=(I-A)[[cos alpha,-sin alphasin alpha,cos alpha]]

A=[[0,-tan((alpha)/(2))tan((alpha)/(2)),0]]then(I-A)[[cos alpha,-sin alphasin alpha,cos alpha

If A=[[0,-tan alpha2,tan alpha2,tan alpha]] and I is 2xx2 unit matrix,then (I-A)[[cos alpha,sin alphasin alpha,sin alphasin alpha,sin alpha]] is (a) these

If A=[(0, -tan""(alpha)/(2)),(tan""(alpha)/(2),0)] , then show that (I+A) =(I-A) [(cos alpha, - sin alpha),(sin alpha, cos alpha)] , where I is the identity matrix of order 2.

If A=[(0,-tan alpha),(2,tan alpha),(2,0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,sin alpha),(sin alpha, sin alpha)] is (a) -I+A (b) I-A (c) -I-A (d) non of these

sin 2 alpha - cos 2 alpha tan alpha =

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is

If A=[(0,-tan (alpha/2)),(tan (alpha/2),0)] and I is 2 xx 2 unit matrix, then (I-A)[(cos alpha,-sin alpha),(sin alpha, cos alpha)] is