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EN of the element (A) is E(1) and IP is ...

EN of the element (A) is `E_(1)` and IP is `E_(2)`. Then EA will be

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EN of the element (A) is E_(1) and EA is E_(2) hence IP will be :

EN of the element (A) is E_1 and IP is E_2 . Hence EA will be

IP of an element is x and EA is y then correct relation is :

A series of concentric ellipse E_1,E_2,E_3,…,E_n is constructed as follows: Ellipse E_n touches the extremities of the major axis of E_(n-1) and have its focii at the extremities of the minor axis of E_(n-1) . If eccentricity of ellipse E_n is e_n , then the locus of (e_(n)^(2),e_(n-1)^(2)) is

Name the elements with highest EN and with highest EA or Delta_(eg)H^(ɵ) .

Name the elements with highest EN and with highest EA or Delta_(eg)H^(ɵ) .

A series of concentric ellipses E_1,E_2, E_3..., E_n are drawn such that E touches the extremities of the major axis of E_(n-1) , and the foci of E_n coincide with the extremities of minor axis of E_(n-1) If the eccentricity of the ellipses is independent of n, then the value of the eccentricity, is

A series of concentric ellipses E_1,E_2, E_3..., E_n are drawn such that E touches the extremities of the major axis of E_(n-1) , and the foci of E_n coincide with the extremities of minor axis of E_(n-1) If the eccentricity of the ellipses is independent of n, then the value of the eccentricity, is