Adding powdered Cu and Zn to a solution containing 1.0 M is each of `Cu^(​2+) and Zn^(​2+)` ions would result into the formation of :-

Adding powdered Pb and Fe to a solution containing 1.0 M each of Pb^(2+) and Fe^(2+) ions would result into the formation of:

Adding powdered Pb and Fe to a solution containing 1.0 M each of Pb^(+2) and Fe^(+2) ions would result in the formation of :

Calculate the potential of a Daniel cell, initially containing 1 litre each of 1M Cu^(2+) and 1M Zn^(2+) after a passage of 1 times 10^5 coulombs of charge . E_(Cu^(2+),Cu)^@=+0.34V, E_(Zn^(2+),Zn)^@=-0.76V

For the cell Zn|Zn^(2+)||Cu^(2+)|Cu if the concentration of Zn^(2+) and Cu^(2+) ions is doubled, the emf of the cell:

For the cell Zn// Zn^(2+) // // Cu^(2+) // Cu , if the concentration of Zn^(2+) and Cu^(2+) ions is doubled , the emf of the cell