A body of mass m = 10 kg is attached to a wire of length 0.3m. The maximum angular velocity with which it can be rotated in a horizontal circle is (Given, breaking stress of wire `= 4.8 xx 10^(7) Nm^(-2)` and area of cross-section of a wire `= 10^(-2) m^(2)`)

A body of mass m = 0 kg is attached to a wire of length 0.3 m. Calculate the maximum angular velcoity with wicch it can be rotated in a horizontal circle (Breaking stress of wire = 4.8 x 10^(7)N//m^(2) and area of cross-section of wire = 10^(-6)m^(2) )

A block of mass 1 kg is fastended to one end of a copper wire of cross- sectional area 1 mm^(2) and is rotated in a horizontal circle of radius 20 cm. If the breaking stress of copper is 5 xx 10^(8)Nm^(-2) , find the maximum number of revolutions the block make in the minute without the string breaking.

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8xx10^(7)N//m^(2). The area of cross-section of wire is 10^(-6)m^(2). What is the maximum angular velocity with which it can be rotated in a horizontal circle?

A body of mass 10 kg is attached to a wire 0.3 m long. Its breaking stress is 4.8xx10^(7)N//m^(2). The area of cross-section of wire is 10^(-6)m^(2). What is the maximum angular velocity with which it can be rotated in a horizontal circle?

A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is 4.8 xx 10^(7) N//m^(2) . The area of cross section of the wire is 10^(-6) m^(2) . The maximum angular velocity with which it can be rotated in a horizontal circle

A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is 4.8 xx 10^(7) N//m^(2) . The area of cross section of the wire is 10^(-6) m^(2) . The maximum angular velocity with which it can be rotated in a horizontal circle

A bob of mass 10 kg is attached to wire 0.3 m long. Its breaking stress is 4.8 xx 10^(7) N//m^(2) . The area of cross section of the wire is 10^(-6) m^(2) . The maximum angular velocity with which it can be rotated in a horizontal circle